Let the Coxeter graph be in its antiflag model, with G acting through a marking μ. Each edge has the form {(p,B),(q,B′)}, with B and B′ meeting in the third point c of the line pq.
(a) The point rule, which goes from each point of B off pq to the third point of its line with p, and from each point of B′ off pq to the third point of its line with q, traces a directed 4-cycle on the quadrangle complementary to pq. The line rule traces, dually, a directed 4-cycle on the four lines missing c. Each rule, followed by the element of order 4 that advances its cycle one step, is a seam from the edges to 4A, and the two rules give mutually inverse elements.
(b) The vertex seam sends an antiflag to the pair of points of P1(F7) with the same stabilizer, and an edge to a harmonic pair of disjoint pairs {{a,b},{c,d}}. Of the two directed 4-cycles a→c→b→d→a and a→d→b→c→a, exactly one has [a,c][c,b][b,a] a nonzero square, and the bracket rule sends the edge to the element of order 4 advancing that cycle one step.
(c) If μ differs from μA by an inner automorphism, the bracket rule agrees with the point rule on every edge; if by an outer one, it agrees with the line rule.
Consequently the seam system for G/C4 formed by the Coxeter edges, the harmonic pairs of pairs and the class 4A, with the vertex seam, the bracket rule and the point rule, is coherent when the marking is in the class of μA, and its monodromy is the nontrivial automorphism otherwise.