Universal Kernel

seam

How are two incarnations of one object matched?

An equivariant bijection between two incarnations of one object; the seams between two incarnations form a torsor under the object’s automorphisms.

0123456∞
the Sylow subgroup fixing both

{0, ∞}⟨z ↦ 2z⟩(1, 246)

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Plate 2.1The seam, for one marking, from the pairs of P1(F7)\Proj^1(\F_7) to the antiflags of the Fano plane, element by element, with the Sylow 3-subgroup that fixes both. It carries neighbours to neighbours.
Definition(Seam)

A seam between two incarnations YY and Y′Y' of an object is a GG-isomorphism Y→Y′Y\to Y'. Seams compose, and the inverse of a seam is a seam.

A seam is the line along which two pieces of cloth are joined. Here the pieces are theories, and the join is an equivariant bijection between the sets in which they meet one object.

Theorem(The stabilizer principle)

Let XX be an object with stabilizer class [H][H]. Then Aut⁡G(X)≅NG(H)/H\Aut_G(X)\cong N_G(H)/H, and for two incarnations YY and Y′Y' the seams Y→Y′Y\to Y' form a torsor for Aut⁡G(Y)\Aut_G(Y) acting by precomposition and for Aut⁡G(Y′)\Aut_G(Y') acting by postcomposition. There are exactly ∣NG(H):H∣|N_G(H):H| of them, and one is written down as soon as a pair of points with equal stabilizers is found: gy↦gy′gy\mapsto gy'.

Proof

If s,s′s,s' are seams, s−1s′s^{-1}s' is an automorphism of YY and s′=s∘(s−1s′)s'=s\circ(s^{-1}s'). The automorphisms of X=GxX=Gx correspond to the points nxnx with n∈NG(H)n\in N_G(H), and nx=xnx=x exactly when n∈Hn\in H.

Proposition(The seams, explicitly)

Let YY be any incarnation of the object of size 28. Each Sylow 3-subgroup PP of GG fixes exactly one point yPy_P of YY, the point with stabilizer NG(P)N_G(P), and P↦yPP\mapsto y_P is the unique seam from the Sylow subgroups to YY.

On P1(F7)\Proj^1(\F_7), yPy_P is the pair of points fixed by PP; in the Fano plane, the unique point and the unique line fixed by μA(P)\mu_A(P); on the Klein quartic, the line through the two points of the curve fixed by ρ(P)\rho(P); in the Coxeter graph, the unique vertex fixed by μC(P)\mu_C(P). Composing these maps and their inverses gives the seam between any two of the five incarnations, and all of these seams commute.

Proof

If PP fixes yy, then P≤GyP\le G_y, which has order 6 and so is NG(Q)N_G(Q) for its unique subgroup QQ of order 3; hence Q=PQ=P and Gy=NG(P)G_y=N_G(P). Since NG(P)N_G(P) is self-normalizing, exactly one point has this stabilizer. The map P↦yPP\mapsto y_P is a GG-map, since gyPgy_P is fixed by gPg−1gPg^{-1}, and a GG-map between transitive GG-sets of the same finite size is a bijection.

Example

The pair {0,∞}\{0,\infty\} is fixed pointwise by z↦2zz\mapsto2z, of order 3, so the seam to the Sylow subgroups sends it to ⟨z↦2z⟩=⟨h⟩\langle z\mapsto2z\rangle=\langle h\rangle, with h ⁣:z↦4zh\colon z\mapsto4z. Klein’s ρ(h)\rho(h) permutes the coordinates cyclically; its fixed points on the curve are (1:ω:ω2)(1:\omega:\omega^2) and (1:ω2:ω)(1:\omega^2:\omega), ω=e2πi/3\omega=e^{2\pi i/3}, and the line through them is x+y+z=0x+y+z=0, a bitangent since

x3y+y3z+z3x∣z=−x−y=−(x2+xy+y2)2.x^3y+y^3z+z^3x\big|_{z=-x-y}=-(x^2+xy+y^2)^2.
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